2500KVA transformer bearing current how much calculation
According to P = 1.732UI, you can calculate the rated current on each side of the transformer.
But the transformer in a short time usually have a certain overload capacity, so the current overload will be greater than the rated value.
Did not give the voltage data to transformer primary and secondary side rated voltage 10KV / 0.4KV as an example:
Primary side rated current:
I = P / 1.732 / U = 2500 / 1.732 / 10 ≈ 144 (A)
Secondary side rated current:
I = P / 1.732 / U = 2500 / 1.732 / 0.4 ≈ 3609 (A)
2500KVA transformer carrying current of 7740A. The calculation method is:
Because P = UIcosφ, so
I = P / (Ucos?) = 2500 KVA / (380 Vx0.85) = 7740A.
Transformer is the use of electromagnetic induction principle to change the AC voltage of the device, the main components are primary coil, secondary coil and core (core). The main functions are: voltage conversion, current conversion, impedance conversion, isolation, voltage regulator (magnetic saturation transformer) and so on. According to the use can be divided into: power transformers and special transformers (electric furnace change, rectification, frequency test transformer, voltage regulator, mine variable, audio transformers, IF transformers.
