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3 core 35 square line threading tube how much

3 core 35 square line threading tube how much RT

Answer:

Electrical appliances are different, the current is also different. The general 2.5 square can be 12.5 with the following .4 square is 20 years below .6 square is 30 years below. But the calculated diameter and the number of amid Easy, but not more than 30%. To the end of the line loss. That depends on what material you are the wire, different resistivity of different materials. A variety of conditions to determine the resistance of the wire, and the resistance and determine the wire is generated by the heat, the wire may be welded to short wire. How much electric power can withstand the electric current, the current depends on its own melting point, the higher the melting point to bear the higher the heat, then bear the higher the electrical power resistance R = ρ (l / s) (resistivity multiplied by the length and horizontal The ratio of the cross-sectional area of the different material resistivity need to check the professional table Joule hot formula Q = I × I × R × t (the square of the current multiplied by the resistance multiplied by the power time) Q = U × U × t / (The voltage multiplied by the current multiplied by the power-on time) Electric power P = I × I × R (the square of the current multiplied by the resistance) P = U × (the voltage multiplied by the power time multiplied by the resistance) Q = U × I × t (voltage multiplied by the current multiplied by the power time) U / R (the square of the voltage divided by the resistance) P = U × I (voltage multiplied by the current)
5 shots × 750W (watts) ≈ 3750W ÷ 220V ≈ 17A (operating current), the starting current of the air conditioner is about 7 to 10 times the running current .... 5 air conditioners can be used with 4 square double Line is supplied separately
Electrical appliances are different, the current is also different. The general 2.5 square can be 12.5 with the following .4 square is 20 years below .6 square is 30 years below. But the calculated diameter and the number of amid Easy, but not more than 30%. To the end of the line loss. That depends on what material you are the wire, different resistivity of different materials. A variety of conditions to determine the resistance of the wire, and the resistance and determine the wire is generated by the heat, the wire may be welded to short wire. How much electric power can withstand the electric current, the current depends on its own melting point, the higher the melting point to bear the higher the heat, then bear the higher the electrical power resistance R = ρ (l / s) (resistivity multiplied by the length and horizontal The ratio of the cross-sectional area of the different material resistivity need to check the professional table Joule hot formula Q = I × I × R × t (the square of the current multiplied by the resistance multiplied by the power time) Q = U × U × t / (The voltage multiplied by the current multiplied by the power-on time) Electric power P = I × I × R (the square of the current multiplied by the resistance) P = U × (the voltage multiplied by the power time multiplied by the resistance) Q = U × I × t (voltage multiplied by the current multiplied by the power time) U / R (the square of the voltage divided by the resistance) P = U × I (voltage multiplied by the current)

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