if the frequency is 60 Hz.
XL2*pi*f*L 2*pi*60*0.9getyouranswer and the substitute it in ohm's law. IV/XL. Inductors and capacitor offer a form of resistance to ac called Inductive reactance and capacitive reactance respectively whch is dependant of da frequency of the supply.
Ohm's law tells you that V I*R, which translates to V I*Z in an AC network, where Z is impedance. We want to know the current I, which we can express as I V/Z. We know the voltage is 110V AC, so to find the current we should find the impedance and calculate it that way. Inductors have an impedance of Z L*w, where w is the frequency in radians per second. 60 Hz means you have 60 complete oscillations (cycles) per second, which is equal to 2*pi*60Hz 376.9 radians per second. Since the L of our inductor is 0.9H, our impedance must be Z 0.9H*376.9rad/s 339.23ohms of impedance. Now that we know the impedance, we calculate the current. I 110VAC/339.23ohms 324.27mA AC.
