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Question:

A 115g mass of aluminum is formed into a right circular cylinder, shaped so that its diameter equals its?

heightCalculate:a) the resistance between the top and bottom faces of the cylinder at 20 degrees Celsius b) Calculate the resistance between opposite faces if the same mass of aluminum is formed into a cube.Please Help!and pleaseee show how to do this problem, I am SO confused.

Answer:

The density ρ of Al 2.70g/cm^3 so 115g occupies 115g/2.70g/cm^3 42.59 cm^3 V of cylinder πr^2h πd^2/4h if d h then V πd^3/4 Therefore d cube root(4V/π) cube root(442.59/π) 3.79 cm Now R ρL/A 1.72x10^-80.0379/(π0.01895^2) 5.78x10^-7Ω Now if the block is a cube then the sides would be cube root(42.59) 3.49cm So R ρL/A 1.72x10^-80.0349/(0.0349^2) 4.93x10^-7Ω
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