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Question:

A 17.9 g sample of iron ore is treated as follows. The iron in the sample is all co?

please help. this is for my AP chem class and im just stuck. If you could tell me HOW to do this problem, that would be most helpful!Also these questions:1. An ore contains Fe3O4 and no other iron. Theiron in a 21.44 gram sample of the ore is allconverted by a series of chemical reactions toFe2O3. The mass of Fe2O3 is measured to be18.2 grams. What was the percent Fe3O4 inthe sample of ore?Answer in units of %.2. For the reactionCH3OH + O2 ! HCO2H + H2O,what is the maximum amount of HCO2Hwhich could be formed from 4.13 g of CH3OHand 16.23 g of O2?Answer in units of g.

Answer:

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Yes I agree with what's been said
mol mass / molar mass mass Fe2O3 10.1g. molar mass Fe2O3 159.sixty 9 g/mol. atomic wt Fe2 fifty 5.8 * 2 111.6 g/mol. (111.6 / 159.sixty 9) * 10.a million 7.06 g Fe. (7.06 / 40 4.6) * one hundred 15.eighty 3% iron interior the ore.
2 Fe3O4 . → 3 Fe2O3 . (18.2 g Fe2O3) / (159.6887 g Fe2O3/mol) x (2/3) x (231.5333 g Fe3O4/mol) / (21.44 g) 0.821 82.1% CH3OH + O2 → HCO2H + H2O (4.13 g CH3OH) / ( 32.0420 g CH3OH/mol) 0.12889 moles CH3OH (16.23 g O2) / (31.9989 g O2/mol) 0.50720 moles O2 0.12889 moles of CH3OH would react completely with 0.12889 moles of O2, but there is more O2 present than that, so O2 is in excess and CH3OH is the limiting reactant. ( 0.12889 mol CH3OH) x (1/1) x (46.0255 g HCO2H/mol) 5.93 g HCO2H
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