Home > categories > Minerals & Metallurgy > Aluminum Foils > A 4kg block of aluminium is( c 900j/kg/degree Celcius) at 450 degrees celcius is plunged quicky into a 20?
Question:

A 4kg block of aluminium is( c 900j/kg/degree Celcius) at 450 degrees celcius is plunged quicky into a 20?

A 4kg block of aluminium is( c 900j/kg/degree Celcius) at 450 degrees celcius is plunged quicky into a 20L bucket of water (c 4180j/kg/degree celcius) initially at 20 degrees CelciusAssume 1That no water evaporates2That all of the heat transferred is used to increase water temp not the bucketCalculate te final temperatuer of aluminium and water mixture when the temperature stops changing.I am a new physics student so if you could include working much appreciated!!!!

Answer:

cover the rack with the foil and make sure it has a lip to hold the fat and juices on the rack or you will have a Smokey, grease mess if not a fire! Good Luckdo you have a skillet with a metal handle? or a large pot would work too but the chicken will not be as crisp.
It will drip a lot in the oven w/o a baking sheet.but if you make a man-made lil sheet for it out of foil that will work.and dont forget to put some foil below it in case it does drip!!!! Happy Cooking!!!!
The foil over the rack will do it when you mean boxed chicken that does mean cooked right ?? if not then I would not recommend cooking the chicken with foil on the rack because of the grease it will be a mess unless it is boneless skinless breast or thighs You can also buy an aluminum disposable pan cheap to If it is a gas oven it can catch fire if the fat drips all over the place.
Because no heat leaves the system through evaporation or conduction to the bucket, the total heat content remains the sameThe water's temperature changes from 20 C to the common final temperature T we want to calculate Hence the water's change in heat content is: ΔQ_water m c (T - 10) Likewise, the change in heat content of the block of aluminium is (using capital C and M for the Alu) ΔQ_Al M C (T - 450) The total change must be zero, so ΔQ_water + ΔQ_Al 0 m c (T - 10) + M C (T - 450) 0 ( m c + M C) T 10 m c + 450 M C T (10 m c + 450 M C)/( m c + M C) (10 C 20 kg 4180 J/(kg C) + 450 C 4 kg 900 J/(kg C)) / (20 kg 4180 J/(kg C) +4 kg 900 J/(kg C)) 2456000 J / (87200 J/C) 28.2 C
cover the rack with the foil and make sure it has a lip to hold the fat and juices on the rack or you will have a Smokey, grease mess if not a fire! Good Luckdo you have a skillet with a metal handle? or a large pot would work too but the chicken will not be as crisp.
It will drip a lot in the oven w/o a baking sheet.but if you make a man-made lil sheet for it out of foil that will work.and dont forget to put some foil below it in case it does drip!!!! Happy Cooking!!!!
The foil over the rack will do it when you mean boxed chicken that does mean cooked right ?? if not then I would not recommend cooking the chicken with foil on the rack because of the grease it will be a mess unless it is boneless skinless breast or thighs You can also buy an aluminum disposable pan cheap to If it is a gas oven it can catch fire if the fat drips all over the place.
Because no heat leaves the system through evaporation or conduction to the bucket, the total heat content remains the sameThe water's temperature changes from 20 C to the common final temperature T we want to calculate Hence the water's change in heat content is: ΔQ_water m c (T - 10) Likewise, the change in heat content of the block of aluminium is (using capital C and M for the Alu) ΔQ_Al M C (T - 450) The total change must be zero, so ΔQ_water + ΔQ_Al 0 m c (T - 10) + M C (T - 450) 0 ( m c + M C) T 10 m c + 450 M C T (10 m c + 450 M C)/( m c + M C) (10 C 20 kg 4180 J/(kg C) + 450 C 4 kg 900 J/(kg C)) / (20 kg 4180 J/(kg C) +4 kg 900 J/(kg C)) 2456000 J / (87200 J/C) 28.2 C

Share to: