A chemist prepares a solution of Aluminum sulfite (Al2(SO3)3) by measuring out 1.5 x 10^2 ?mol of aluminum sulfite into a 350.mL volumetric flask and filling the flask to the mark with water.Calculate the concentration in of the chemist's aluminum sulfite solutionRound your answer to 2 significant digits.i have 4.29x10^2 but i don't know if that's correct.
molar mass 294.15 g/mol 1 ?mol 1 x 10^-6 mol, or 1 mol 1 x 10^6 ?mol moles 1.5 x 10^2 ?mol(1 mol)/(1 x 10^6 ?mol) 1.5 x 10^-4 mol molarity moles solute/L of solution L of solution 350mL(1 L)/(1000 mL) 0.350 L molarity (1.5 x 10^-4 mol)/(0.350 L) 4.29 x 10^-4 M To 2 sig figs, molarity 4.3 x 10^-4 M Your answer seems to be off by a factor of 10^6, or a millionHope this is helpful.
