A sofa costs $10 less than twice the price of a chair. What is the cost of each if the total cost is $716?

Its algebra and its hard help PLEASE

Answer:

For problems like those is that I hate math, but let me see if I'm right: $10/2 + 716/x 10X = 716 * 2 10X = 1432 X = 143.2 The price of each is $143.20 Hey! I really hope this helps, but note that I'm not really good at math, especially online but I wanted to help Good luck ^_^

The Chair costs 358 dollars and the sofa costs 348 dollars but i could be wrong but im pretty sure thats it. Hope I helped :)

first you can divide $716 by 2 then subtract 10 to find the of one sofa chair which is $338.00

Let's say the price of the chair is X. This would make the price of the sofa 2X-$10. So the total cost would be X+2X-$10=$716 or: 3X-10=716. Now all you have to do is solve for X. 3X-10=716 3X=716+10=726 X=726/3=242 Chair is $242 Sofa is $474

Chair=x Sofa = 2x-10 Total = 716 x + 2x - 10 = 716 3x -10= 716 3x=726 x=242 chair cost $242 sofa cost $474