A window washer is standing on a scaffoldsupported by a vertical rope at each end. Thescaffold weighs 145 N and is 3.02 m long.Assume the 675 N worker stands 1.28 m fromone end of the scaffold.What is the force on the rope farther fromthe worker?Answer in units of NWhat is the force on the closer rope?Answer in units of N.
461.40N at the nearer end and 358.60N farther end.
Force from scaffold alone = (145/2) = 72.5N. on each rope. 675/ ((3.02/1.28)) + 1) = 200.93N. on the further rope, and (675 - 200.93) = 474.07N. on the nearer. Total tension further rope = (200.93 + 72.5) = 273.43N. Total tension nearer rope = (474.07 + 72.5) = 546.57N.
Analyzing the force diagram Forces in the Upward direction:...T1,T2 (tension of the ropes) Forces in the Downward direction...M1g (scaffold), M2g (man) Fnet = 0 T1 + T2 = M1g + M2g Analyzing the moments about the center T1 is nearest man T1(1.51) =M2g(1.51 - 1.28) + T2(1.51) T1 + T2 = (675 + 145)= 820 T1 - T2 = ((675)(1.51 - 1.28))/1.51 = 102.81 sum the two equations 2T1 = 922.81 T1 = 461.5 N T1 + T2 = 820 T2 = 358.6 N
