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Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum ar

Problem #1: Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum are needed to form 3.4 moles of Aluminum oxide?Hint: This is a simple ratio problem. Just use the molar ratio from the balanced equation. This was covered in 5.09. Mass is not involved.Problem #2:Determine the number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen gas. (Check for diatomic elements). Can U Show me how 2 balence and how 2 and what 2 cancel. PLEASE I NEED YOUR HELP!

Answer:

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#1 The balanced equation will be: 4 Al + 3 O2 -- 2 Al2O3 Since the ratio of aluminum to aluminum oxide is 2:1, just multiply the moles of Al2O3 by 2 to get the moles of Al needed. #2 The reaction is between H2 and N2 to give NH3. H2 + N2 -- NH3 To balance it, since you have N2 on the left, you'll form 2 NH3 on the right. That gives you 6 H on the right, so you'll need 3 H2 on the left. The balanced equation is: 3 H2 + N2 -- 2 NH3 So get to the answer, first convert the grams of H2 into moles by dividing the the molar mass of H2. Then, use the coefficients of the equation to convert moles of H2 into moles of NH3. Finally, use the molar mass of NH3 to convert moles of NH3 into grams of NH3.
Aluminum Oxide Reaction
This Site Might Help You. RE: Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum ar Problem #1: Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum are needed to form 3.4 moles of Aluminum oxide? Hint: This is a simple ratio problem. Just use the molar ratio from the balanced equation. This was covered in 5.09. Mass is not...

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