An iron ore contains 62 percent of Fe2O3. How much weight of iron is obtainable from one ton of ore?
Use % composition. One ton is 2000 lbs so multiply 2000 by 0.62 to get the amount of Fe2O3 in the ore. 2000 x 0.62 1240 lbs Fe2O3 Now find the % Fe in Fe2O3 Fe 55.8 x 2 111.6 O 16 x 3 48 Total 159.6 Fe% 111.6 / 159.6 69.92% by mass of Fe2O3 Multiply 0.6992 by the amount of Fe2O3 in one ton. 0.6992 x 1240 lbs 867 lbs Fe in 1 ton of ore.
