Pretty please can someone show me the steps on how to do this one?Calculate the mass in grams of iodine (I2) that will react completely with 43.7 g of aluminum (Al) to form aluminum iodide
Aluminum Iodide is AlI3 - one aluminum atom bonded to three Iodine atoms. Look up the atomic weight of Aluminum. Look up the atomic weight of Iodine. Al / 43.7g =3 X Iodine / mass Mass of Iodine required = 43.7 X Atomic weight of Iodine X 3 / Atomic weight of Aluminum
easily the guy earlier me did it precise yet made a mistake at one ingredient 0.07 mole is the # of moles of Al which desires to get replaced to moles of product, and then returned to come across mole of iodide. as quickly as thats stumbled on then you quite can use the MW to alter it to grams.
