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Question:

Calculate the mass of aluminium in 8.0g of aluminium sulfate Al2(SO4)3.?

Can someone please explain to me how to do thisI understand the mole everything I'm just not 100% sure of the correct equation to work this outThank you.

Answer:

try expanding foam thro well spaced holes in your plaster board leave for 2 to 3 days then trim of excess and redecorate
Half inch syrofoam insulation will do the trickIt comes in 8 ftby 4 ftsheets and will have to be paneled over
Step 1 - find moles of Al2(SO4)3 Step 2 - find moles of Al 2 mol Al for each 1 mol of Al2(SO4)3 Step 3 - convert moles of Al to grams Simply use the unit-factor method and the appropriate conversion factorsStep 1 Step 2 8.0g Al2(SO4)3 x (1 mol Al2(SO4)3 / 342.3 g Al2(SO4)3) x (2 mol AL / 1 mol Al2(SO4)3) x (27.0g Al / 1 mol Al) 1.3 g Al to two significant digits Step 3 Your mass of 8.0 grams has two significant digits and limits the precision of the answer to only two significant digits Do the chain calculation shown above, and then round to the correct number of significant digits1.26 is rounded to 1.3 Round off only once at the end of the calculationRounding at each step will introduce too much round-off error.
try expanding foam thro well spaced holes in your plaster board leave for 2 to 3 days then trim of excess and redecorate
Half inch syrofoam insulation will do the trickIt comes in 8 ftby 4 ftsheets and will have to be paneled over
Step 1 - find moles of Al2(SO4)3 Step 2 - find moles of Al 2 mol Al for each 1 mol of Al2(SO4)3 Step 3 - convert moles of Al to grams Simply use the unit-factor method and the appropriate conversion factorsStep 1 Step 2 8.0g Al2(SO4)3 x (1 mol Al2(SO4)3 / 342.3 g Al2(SO4)3) x (2 mol AL / 1 mol Al2(SO4)3) x (27.0g Al / 1 mol Al) 1.3 g Al to two significant digits Step 3 Your mass of 8.0 grams has two significant digits and limits the precision of the answer to only two significant digits Do the chain calculation shown above, and then round to the correct number of significant digits1.26 is rounded to 1.3 Round off only once at the end of the calculationRounding at each step will introduce too much round-off error.

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