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Question:

Calculate the mass percent composition of iron for the first one of these iron ores?

Fe2O2 (hematite)

Answer:

The molar mass of Fe2O2 143.7 g/mole (2xFe 55.85g/mol + 2xO 16.0 g/mol) 2x55.85 / 143.7 0.777 (77.7% Fe) HOWEVER, Hematite is Fe2O3 (not Fe2O2), so the correct answer would be 69.9%.

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