72F tank air. 100psi72F outside air.72F engine block.Air into spark plug hole at top center. Air decompresses and chills. 15psi at 30F (just example)Stop the engine at bottom
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Huh? How do you maintain the stable air temperature? The pressure is possible, but the temp would be a challenge. Why 72F? Is this some sort of magic temperature?
Air tight assumes an absolute that cannot exist. There would be bleeding within the system due to cooling and heating, variations in barometric and atmospheric pressures. This also assumes that all systems would remain the same. If this were absolute then the wait would be irrelevant whether a week or 100 years. Setting all systems at 72 degrees (I'm unsure how you arrived at that number.) would make it less stable, not more. Variation is the key, and all systems should be calibrated to within 10 tolerances of the preceding variable. In answer to your question, no the psi would not be 100 probably closer to 86 and the temp would probably be lower by 6 to 8 degrees. Of course this answer is also subject to variations dependent upon the nature of actual changes within the engine.
I think, from your question, that the pressure and temperature of the air in the tank don't matter. You have defined the cylinder as being filled at top center with 30F air at 15 PSI. Work is then done to move the cynlinder to the bottom position, with will reduce the pressure by the compression ratio. For this example, lets assume 10::1. The gas formula is PV=nrT. For our purposes, the Pressure times the Volule divided by Temperature is constant. For this formula, all temperatures are absolute temperatures. We'll use the Rankine scale, which adds 459.67? to the Fahrenheit scale to give Rankine degrees. What is the volume of the cylinder? Lets assume a big engine, like a 409 cubic inch displacement V8. That gives us a volume of 51.125 cubic inches for the cylinder. We know the temperature, volume, and pressure at the beginning. We know the temperature and volume at the end, and want to know the pressure. Pi = Pressure initial Vi = Volume initial Ti = Temperature initial Pf = Pressure final Vf = Volume final Tf = Temperature final Pi = 15 psi (given) Vi = 5.1125 (from compression ratio) Ti = 489.67?R Pf = unknown Vf = 51.125 (from assumption) Tf = 531.67?R (Pi * Vi)/Ti = (Pf * Vf)/Tf (15 * 5.1125) / 489.67 = (Pf * 51.125) / 531.67 Solving for Pf gives Pf = 1.63 psi The temperature difference between 30 degrees and 72 degrees does not come close to making up for the volume difference between the top and bottom of the stroke.
Mythbusters did this, with a vaporizing wheel in a cold river. It turned itself but extremely slowly. But what he is saying, the atmosphere is a source of heat which can do work on cold decompressed air. Now if he uses a('air to air' atmospheric) heat exchanger for the cold air leaving the engine and used a compressor to also add HEAT needed to reach full recompression, it may be practical. Remember the energy source of compressed air is the latent heat of the atmosphere(which is of course, the sun). 100% of the energy to access that energy is wasted (electric, chemical, whatever) as heat. Every air compressor is 200% ENERGY efficient like a heat pump. What would happen if that 100% wasted heat energy was used to recompress air? Is it possible?
