Channel 10, 6 meters long, two ends fixed, how much weight can the middle bear?
For concentrated loads: M=1/4PL+1/8gL, =1/4 * 600P+1/8 * 0.1 * 600 * =39.4 * 1400=55160kg-cmP= (55160-1/8 x 0.1 x 600 x) x 4/600=337.73kg, that is, midspan can withstand the force of 337.73kg.
Under the maximum bending moment calculation formula: M=1/8GL?? -1/8gL??, (L=600cm, G: the calculation of the maximum uniform load, G: ibid.)
It's important to see where you've used it. If you allow it to bend, you'll have to bear a lot of weight, but vice versa
