What is the percentage of Fe in an iron ore if 4.5 g of the ore yielded 2.40 g of Fe2O3?I don‘t understand how to do this???Thanks!
They are probably stuck on the inside of the tyre, so they will not do any harm.
No point in removing them. If the tire is ever removed at a later time, then you can remove it.
First, we should find the percentage of iron in iron (III) oxide using atomic and formula masses: % iron [(Fe2)(100%)] / (Fe2O3) % iron [(111.694)(100%)] / (159.6922) % iron 69.943303% Next, we take that percentage of 2.40 g of Fe2O3 to find the mass of iron in it: (2.40 g)(0.69943303) 1.6786392 g of Fe Finally, we calculate the percentage of iron in 4.5 g of an iron ore using this equation: % iron in iron ore [(mass of iron)(100%)] / (mass of iron ore) % iron in iron ore [(1.6786392 g)(100%)] / (4.5 g) % iron in iron ore 37.303093% or 37% rounded to two significant figures Answer: The percentage of Fe in an iron ore is about 37%.
