when you solve for the of moles for any cmpd/element etc for emperical formula - what do you do if you have half of a mole.ex: if you get to 2.4 or 2.5 or 2.6 moles of Aluminum, do you round up? how does that work?sorry but thanks
If you get 2.5 for one of the mol values you multiply all mol values by 2 Example : mol C 2.5 mol H 6 multiply by 2 mol C 5 mol H 12 Empirical formula C5H12 mol values 2.4 is tricky and I would be suspicious of such a value But : 2.33 is possible C 2.33 H 4 Remove fraction - multiply by 3 C 2.333 7 H 43 12 Empirical formula C7H12 2.66: multiply by 3 C 2.66 H 5 C 2.663 8 H 53 15 Empirical formula C8H15 You NEVER round up from 2.6 to 3 or round down 2.3 to 2 BUT a SMALL amount of rounding is permitted after multiplying : as above: 2.33 3 6.99 OK to round to 7
