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Chemistry Question on solving area, mass, and density?

I'm really stumped on this question, any help would greatly be appreciated!The aluminum foil on a roll has a total area of 25m^2 and a mass of 1496 gUsing a density of 2.7g/cm^3 for aluminum, determine the thickness in millimeters of the aluminum foil.

Answer:

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I have tried it onceI have to say that not only was I feeling light-headed, nauseous, sick and really in a bad mood, but I also found that it made me feel a little better in the endmy mother on the other hand found nothing wrong with it, except for the fact it wasn't the best tasting thing in the worldyou got to try it i guessi wouldn't do it again, no way jose!
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Given: Area: 25 m^2 Mass: 1496 g Density of aluminum: 2.7 g/cm^3 Want: thickness (in mm) Notice that you have three components that, if you cancel them out, will end up leaving you with a single dimension unit for thickness (in m or cm)First, either convert area to cm or density to g/m^3; I'm going to convert area to cm to match the units of density: (25 m^2) (100 cm / 1m)^2 - remember to square the whole conversion, not just the m part So 25 m^2 25 10000 cm^2/m^2 250,000 cm^2 (canceling the m^2 units) Now, we just manipulate the density by multiplying it by the given area and mass (which we use as conversion factors), canceling the units until we are left with only units of thickness, cm: (2.7 g/cm^3) (1 / 1496 g) (250000 cm^2) 451 / cm Reciprocate it to be 1/451 to get cm in the numerator 451 / cm 1/451 cm 0.0222 cm Convert cm to mm 0.00222 cm (10 mm / 1 cm) 0.0222 mm or 2.2210^-1 mm It's a pretty small number but it makes sense, because aluminum foil is very thinHope this helped :)

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