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Question:

copper wire 3mm dia wound about cylinder whose length 12cm dia 10 cm to cover the entire cylinder . what is th

the length and mass of the wire assuming density of copper to be 8.88 gm per cc?

Answer:

Do you really mean mass? I suspect not. What you are really asking is the weight. Ask your physics teacher to explain what the difference is.
First you need to figure out how many loops of copper you will need around the cylinder. Do this by taking the length of the cylinder and dividing by the width of the copper wire. 12cm / 3mm x 10mm/cm = 40 loops Now, what is the length of each loop? The circumference of the cylinder: C = pi x D C = 3.14159 * 10cm = 31.4cm Total length of copper wire is number of loops times length of each loop. L = 1256 cm Now, to get the mass of copper we need to know its volume. We already have its length, but since it's a long thin cylinder we also need to figure out its cross sectional area: A = pi x (D/2)^2 = 0.071 cm^2 Calculate the volume of copper: V = A x L = 89.2 cc Now, the mass of copper is the volume times the density given: m = V x density = 792 grams of copper

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