A copper wire has a length of 5.0 m and a diameter of 3.0 mm. Under what load will its length increase by 0.3 mm? I know that the answer is 47 N I just don't know how this is obtained.
confident by way of fact copper twine isn't a suitable conductor. It relies upon on what you're doing nonetheless as to in case you incredibly ought to account for that or no longer. I never had to take something previous worry-loose circuits training yet in those training we in simple terms assumed the resistence of the twine to be 0 regardless of the actuality that it wasn't. i'm uncertain how lots the twine is factored in in actual purposes.
Hello E*A/L0 = F/?L E = Young's modulus for copper = 100 to 130 kN/mm^2 A = area of cross section in mm^2 L0 = initial length ?L = extension F = force plugging your data in, keeping it all in mm or mm^2, and using E = 100 kN/mm^2: F = E*A*?L/L0 F = 100*10^3 N/mm^2 * pi*1.5^2 mm^2 * 0.3 mm / 5*10^3 mm F = 10^5*pi*1.5^2*0.3/5*10^3 F = 42.4 N With E = 110 kN/mm^2 or 120 kN/mm^2 you will come to the given result. Regards
