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Question:

Does a Heavier Motorcycle equal Shorter Braking Distance?

I say hogwash, but can‘t find proof. Uncle says all the weight moves to the front and that equals stopping faster. I say apply that to trains made of steel and iron and trains made of cardboard and cardboard train obviously stops first.

Answer:

Brakes on a heavier bike can generate more stopping force but the heavier the bike, the more stopping force is required to stop in the same distance. Bottom line is that bikes (at least performance bikes) are designed with brakes and tyres that can create the best achievable stopping distance. In numbers they can all produce a maximum deceleration of just over one G (on a good, dry surface).
DC has massive losses when transmitted large distances. The lines must be large (heavy and expensive), so as to have minimum resistance. AC can be passed through a transformer, boosting the voltage to very high potentials, and by Ohm's law, if the voltage is higher, the current is lower. It is current through resistance that causes transmission losses (R x I^2), so by lowering the current, losses are minimised. Any losses of voltage at the receiving end of the high voltage line can be compensated for by transformer design, when the voltage is dropped back to domestic voltages. DC cannot be transformed.
Here's the thing. You want enough weight to stop the front skidding but the more weight you have the more grip you need sorather than do the maths, if the bike can do a front wheel stand which many can then it means you have enough weight. Any more is pointless. Since the front wheelstand is the limit to how fast you can stop, a long bike is what you want. These are harder to lift the rear with.
He never cracked a physics book did he? Seeing as how your asking I s'pose you never have either.

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