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Easy question on the mass of an element and its ion!?

Can you answer these questions?a)The mass of one mole of 27Al atoms is 26.9185 gGiven that the Avogadro constant equals 6.0225 x 1023 and the mass of one electron equals 9.1091 x 10-28 g, calculate the mass of one mole of 27Al3+ ions.b)Calculate the percentage difference between the mass of 27Al atoms and 27Al3+ ions, and use this to show why the mass of electrons are negligible in normal laboratory use of aluminium and other chemicals.Thank you!

Answer:

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Here we gosince 26.9185 g is one mole of aluminum you can say that that means that you have one mole of Al - Al3+ + 3 moles of electrons one electron has a mass of 9.1091 E-28, each atom gives three, so multilply by three and then by 6.0225E23 to get the mass of 3 moles of e- this give mass of the lost electrons in gramssubtract from 26.9815 and you have mass of one mole Al3+, for part B just take the difference in the two and divide by the actual mass, multiply by one hundred and you have a really small percentage.one that doesn't matterSorry I don't have a calculator.

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