the mass of an excavator is twice that of a farm tractor. the sum of their masses is 21.9 ft . find both massesand how did you get the answer, I don't get how to do it.if anyone could explain it would help alot. thanks. :)
If the sum of their masses is basically 2n + n (the mass of the tractor times two (2n) = mass of the excavator plus the mass of the tractor alone (n), you could do in terms of algebra: 21.9 = 2n + n Combine like terms. 21.9 = 3n To undo the n times 3, divide both sides by three. 21.9 = 3n ___ __ 3 3 n = 7.3 You could also just divide 21.9 by three since it's really just the mass of the tractor three times. 21.9/3 = 7.3 Hope I helped!
set up an equation: 21.9=2t+t with 21.9 standing for excavator, and t for tractor simplify to get 21.9=3t divide 21.9 by 3 t=7.3 (that's the mass of the tractor) for the excavator, multiply 7.3(2) to get 14.6 tractor=7.3 excavator= 14.6
well if their sum is 21.9 ft. and the excavator is twice that of the farm tractor then the farm tractor would be 7.3 ft and the excavator would be 14.6 ft seeing as 14 would be twice the amount of 7 and 7 plus 14 is 21 and the 3 plus 6 is 9 so it would equal 21.9. and you would get the answer by dividing 21.9 by 3 being that the farm tractor is 1 part and the excavator is the other 2 parts, i hope i helped and im pretty sure that is correct but if anyone else reads this and finds something wrong please correct me
