125.0 gram bars of aluminum and copper are heated to 275.6°C in a colorimeter that doesn‘t allow heat to be exchanged wit the environment. The two bar are dropped into a colorimeter containing 250.0 gm of water at 10.9°C.What is the final temperature of the water if the specific heat capacity of aluminum and copper are 0.275 calories/gm/°C respectively? 1 calorie 4.184 joules
Q (heat) mc(change in temp) you only gave one specific heat for the two metals. Q loss Al 125 ( 0.275) ( 275.6 - Tf) Q loss Cu 125 ( 0.275) ( 275.6 - Tf) I'm using the same specific heat because you only gave one. this should probably be different Q gain water 250 (1) (Tf - 10.9) . set equal and solve for Tf (final temp) Q gain total Q loss 250(Tf - 10.9) 125 ( 0.275) ( 275.6 - Tf) + 125 ( 0.275) ( 275.6 - Tf) 2Tf - 21.8 151.58 - 0.55Tf 2.55Tf 173.38 Tf 67.99 degrees C
mc(delta)T -mc(delta)T mmass cspecific heat (delta)Tchange in tempinitial tempfinal temp just plug in numbers it'll work
