seriously dnt no how to do that need help!! if u can show it to me step by step plzz! also find the number of moles in 0.2835g aluminum bromate
Problem 1 - 20.0 grams of HClO4 Nuclear weight of H 1.001 Nuclear weight of Cl 35.453 Nuclear weight of O 15.999 Therefore each mole of HCLO4 is 1.001+35.453+415.999 100.450 grams 20.0 grams (1 mole/100.450grams) .19910403185664509706 moles Rounded to 3 digits (as is the input): 20.0 grams .199 moles Problem 2 - 0.2835g of Aluminum Bromate I believe the formula for aluminum bromate is Al (BrO3)3Nuclear weight of Al 26.981 Nuclear weight of Br 79.904 Nuclear weight of O 15.999 So, each mole is 26.981 + 3 ( 79.904 + 3 15.999) 410.684 0.2835 grams (1 mole/410.685 grams) .00069031009167610212 moles Rounded to 4 digits (as is the input): 0.2835 grams .0006903 moles 6.90310^(-4) moles
