Hey guys,So I've been going to gym for a long time.Last year I went for a month (nov - december) and I had results but when I re-entered on february (school's fault :/) I started over everything and I've had no results at all (yes from february all the way to december), I'm doing it wrong I know,Any foods you recommend me?I weight 66.5 kg (164.6 lb) and my height is 1.7 meters or 5.57 ft.Help, please? I really really appreciate it guys
molecular Na2S + H2SO4 Na2SO4 + H2S ionic 2 Na+ + S2- + H2SO4 2 Na+ + SO42- + H2S net ionic S2- + H2SO4 SO42- + H2S
2Al?? + 3H??? SO??? - 3H??? (g)+ 2Al?? SO??? (s) i believe this is it
A balanced ionic equation means that only the ions that have reacted and come together are listedWater (implied by dilute solutions) will not be listed for ionic reactions because it didn't react to form anything newAlso, remember, that water completely isolates each ion by dissolving it; dissolving salt (NaCl) will have Na+ and Cl- ions floating aroundIn a NET IONIC EQUATIONOnly insoluble compounds are shown in a complete balanced ionic equation, but you're not dealing with a net ionic equation, so Let me show you(Al +3)(aq) + (H2SO4)(aq) becomes: (Al +3)(aq) + (SO4 -2)(aq) + 2(H+)(aq) Now, balancing the equation brings: 2(Al +3)(aq) + 3(SO4 -2)(aq) + 6(H+)(aq) Now, finish with the products2(Al +3)(aq) + 3(SO4 -2)(aq) + 6(H+)(aq) - Al2(SO4)3 (aq) + 6(H+)(aq) Remember, Al2(SO4)3 should only be shown if it is insolubleSince sulfate salts are soluble (execpt for a few exceptions), Al2(SO4)3 should be shown as 2(Al +3)(aq) + 3(SO4 -2)(aq)So, the equation should be: 2(Al +3)(aq) + 3(SO4 -2)(aq) + 6(H+)(aq) - 2(Al +3)(aq) + 3(SO4 -2)(aq) + 6(H+)(aq) since all compounds were dissolved and remained dissolvedI guess there wouldn't be a new ionic equation, so so I THINK this is the balanced ionic equationHope this helpedJust do the same for hydrochloric acid (HCl) since it is also aqueous.
