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Question:

Four electrical components are connected to a 120v household circuit. The light bulb dissipates 100W, the e?

Four electrical components are connected to a 120v household circuit. The light bulb dissipates 100W, the electric heater 1800W, the stereo 350W, and the hair dryer 1200W. The fuse protecting the circuit is a 20A fuse. Will the fuse blow? Justify your decision with calculations and explanations.

Answer:

P okorder
28.75 A : it will blow. The solution is to turn off the heat when you use the hair dryer, or vice versa. The stereo and light bulb are not high enough to make a difference.
Yes. adding up all the power gives 3450 W total. using PVI we find, 3450 120I I 28.75 A when the current rating of a fuse is exceeded it breaks the circuit. The total current of the circuit exceeds 20 A and the fuse will blow.
Total power dissipated 3,450W. (3450/120) 28.75A., so the fuse blows. The powers are additive, then power in watts (voltage x current), so dividing power by voltage will give the current figure. W EI, I W/E. I is current in amperes, E is voltage, in volts. What more can I say?

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