Aluminum Chloride, AlCl3, can be made by the reaction of aluminum with chlorine according to the following equation:2 Al + 3Cl2 2 AlCl3What is the limiting reactant if 20 grams of Al and 30 grams of Cl2 are used, and how much AlCl3 can form?Any help whatsoever is much appreciatedAnd if you could show your work that would be fantasticthanks
