A 2.2 KW motor will require a lot of electricity a day
First you have to determine whether the motor is working under the rated load at 2.2 KW, which is 24 hours a day Electricity is 2.2 * 24 = 52.8 degrees. Don't need to be multiplied by three.
The actual power of the three-phase ac motor is 1.732 UIcos phi Three-phase ac motor is used for the power of Q = Pt Among them: Cosine of phi: the power factor for the motor is 0.85. P: the actual power of the motor, unit: kW. U: the actual voltage of the motor, unit: kV. I: the actual current of the motor, the average of the three phase current, unit: A. T: the actual running time of the motor, unit: hour. Q: the actual power of the motor, the unit kWH.
It is not accurate to calculate simply because you are not considering the load rate of the motor, and the load rate of the pump is less than 75%. The most accurate method is to install the meter.
If it's a resistivity load you're doing the right calculation, and you can't do that with the perceptual load. Rated power components during normal work is the definition of the maximum power output, but the actual power calculation of the equipments should be less than the power of the motor, that is to say, under the condition of normal configuration, motor load amounted to less than one hundred percent. Electric power can't be calculated accurately without electricity
