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Question:

a sample of aluminum chloride has a mass of 37.2 g. how many aluminum ions are present?

how many chloride ions are present? how many chlorine ions are present? what is the mass in grams of one formula unit of aluminum chloride?

Answer:

Aluminum Chloride is simply AlCl3 So In each mole of AlCl3 there are 1 mol of Al 3 mol of Cl We know (from periodic table), 1 mol of Al weighs 26.98 g 1 mol of Cl weighs 35.47g so 1 mol of AlCl3 weighs 26.98g + 3x35.47g = 133.39 g sooo moles of AlCl3 = 37.2 g /133.39 g/mol = 0.279 mol in one mol of anything, there are 6.02 x 10 ^ 23 of that thing... so we have 0.279 mol x 6.02 x 10 ^ 23 molecules /mole = 1.68 x 10 ^ 23 And, we know one molecule of AlCl3 dissociates into one Al ion and 3 Cl ions sooo 1.68 x 10 ^ 23 AlCl3 ions dissociate into 1.68 x 10 ^ 23 Al ions so answer is 1.68 x 10 ^ 23 Al ions

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