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Question:

How many grams of aluminium are required to react with 35 mL of 2.0 M of hydrochloric acid?

How many grams of aluminium are required to react with 35 mL of 2.0 M of hydrochloric acid?

Answer:

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I wouldn't waste my money on a roto-saw ever againthey don't work well and they make a ton of noiseAnd they cut straight lines as easily as it is to push a chain up hillIn other words, impossibleIf you want something that cuts metal, a hack saw sounds in orderIf you want something that can scroll then a hack saw is not what you wantIf whatever you cut you want a straight line, a circular saw works quite well, but can still cut not straightThe best advice I can give is for you to decide what the material is you want to cut and what sort of cut you wantThen research what tool works best for the applicationJig saws can cut scrolls in wood or metal, depending on what blade you insert but they tend to make a rough cut edgeAlso, for straight lines, they are difficult to get good resultsNot impossible but you will need a lot of experienceOne final piece of advice for a novice cutter; never try to make your final cut your first cutWhat I mean is that if you lay out a line, cut close but not on the lineThen, using a file or sand paper or wood plane, trim down to your final layout lineMy neighbor just can't get that lesson through his headHe always tries to make the final cut the first time and ends up with either a horrible looking project OR having to do it overHope this helps'')
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Al + 3HCl - AlCl3 + (3/2)H2 I chose to use an equation with a fractional coefficient because it simplifies the ratio I want to useThe substance with the fraction is not involved in the calculationmoles HCl - (2.0 mol/L) (0.035 L) 0.070 mol The molar ratio between Al and HCl is 1:3 1 is to 3 as x is to 0.070 x 0.023333 mol (I'll keep a few guard digits, this is moles of Al that reacts) 0.023333 mol times 26.98 g/mol 0.6295 mol Rounded off to two sig figs, 0.73 g Edit: oops, 0.63 g
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