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Question:

How to find volume of silo with radius and height?

The silo is in the shape of a right circular cylinder 8 ft. in radius and 7 ft tall, and is topped with a right circular cone 3 ft, tall.a) Find the volume of the silo.b) If the silo is filled full with grain which is worth $150.00 for every 7 cubic feet, how much is the grain in the silo worth?

Answer:

a) (8x8x3.14x7)+(8x8x3.14x3)/3=669.86666666... ft^3 b) 669.866666667/7x150=14,354.2857143 I'm pretty sure, I checked it a couple times, but how can you be sure you checked it right...? Good explanation above of what I just did, just try to ignore th pi parts, it will probably jsut confuse you, but yes, that will keep things exact.
the quantity is comparable to: one million/2 * 4PIr^3/3 + h*PIr^2 (one million/2 the quantity of a sphere of radius r plus the cylindrical quantity) the place h is the peak of the cylinder, not the silo. one million/2 * 4*7^3PI/3 + h*7^2PI = 5000 Multiply the two factors by skill of three and multiply words out giving: 686PI + 147hPI = 15000 or 147PIh = 15000 - 686PI h = (15000 - 686PI)/147PI h = 27.813934 ft. you may desire to function yet another 7 ft for the single million/2 sphere on suitable.
First you need to find the volume of the cylinder, using area equals pi times r^2 so 448 pi Next, the volume of the cone, using 1/3 base times height so 64 pi add them together to get the total volume so 512 pi for the answer to question a (you can multiply that if you want, but I like keeping things exact) Next, you divide the 512 by 7 to find the amount of $150's and multiply it by 150 to get your answer for question b

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