Use the reaction below to answer the following questions.2 Al(s) + 6H2O(g) ? 2 Al(OH)3 + 3 H2aDetermine the oxidation numbers of each element in both the reactants and products of this oxidation-reduction reaction of aluminum.bWhich element is organized, or loses electrons, in this reaction?c.Which element is reduced, or gains electrons, in this reaction?Please help me!
If i will undergo in ideas the articles I even have examine, the only area of the MacBook it somewhat is aluminum is the shell that covers the keyboard, the rest continues to be plasticThe Aluminum one gets scratched somewhat actuallythere became yet another question corresponding to yours.
2 Al + 6 H2O 2 Al (OH)3 + 3 H2 Al starts as neutral element with a zero charge on the left side Al goes to an Al +3 on the right sideAl must lose 3e in order to show a +3 chargeAl Al+3 + 3e H goes from a +1 charge on the left side to a neutral element on the right sideH must gain one electron in order to balance the positive charge and end up neutralH+1 + 1e H OK, there are the two half reactions, now they have to be balanced for the number of electrons transferred and for the general balancing of the equation3H+1 + 3(1e) + 3 H All Right!! This balances it for one aluminum but this has to be doubled to balance the entire equation2 Al 2 Al+3 + 6e 6 H + 6e 6H or 3H2 Which element is oxidized (not organized) or looses electrons? Looks to me like Al looses electronsWhich element is reduced or gains electrons? Hummm, seems to be the H.
