its for my extra credit!!!I figured out that for density of an aluminum foil is 2.7g/cm^3.And I also know that the formula for cm^3 is Length X Width X Thickness.
get a thinner blanket make sure its no to thick or thinAnd If i were you I would not worry but it always good to consult your family dooctor.
Maybe you're a cold hearted evil childOr maybe you were just cold lol
You need more information: starting with how many grams are in one (or 12) can(s), and how thick the foil is to beTake the weight of a can in gramsMultiply by 12, since you have 12 cansThen divide that by 2.7 to get cm^3Divide that by the thickness of the foil to find cm^2Finally, divide that by 30.48 cm 12 to find the lengthWithout the weight information, we can try to fake it as follows: Let's make some estimates, with some gross assumptions: Let's say a can is 6 high and 2.5 in diameter and made out of the same foil we want to produce, and assume the can is just a plain cylinder, with no pull tabs or indentationsThen the area of the aluminum in the can is: pi (1.25)^2 x 2 (top and bottom) + 2.5 pi 6 (around the sides) sq inso we have pi ( (1.25^2) 2 + 15 ) sq in or about 57 sq inThen since we have 12 cans, and want to make a strip 12 wide, the two 12's cancel out and we'll have a sheet of aluminum which is 57 long and 12 wide57 is 1.4478 metersSanity check: each can is 6 high (we presume), so it takes two of them to make 12, one above the otherIf we just unrolled the sides it's 2.5 pi inches about 7 1/2 or 8 inches of material8 x 6 pairs of cans 48, then when we add in the tops and bottoms (presumably after melting them down and making it all into foil), we'd get to 57If the foil is thinner than the can material, or any of these estimates are off, then the real numbers could be wildly different from thisBut it suggests an approach to the problem.
