Kent has a 2-ft by 2-ft square floor to cover with tiles. He has 38 tiles. Twelve of the tiles are 4-inch by 4-inch squares, ten are 4-inch by 8-inch rectangles, and the remaining 16 are 2-inch by 8-inch right triangles. What is the smallest number of pieces Kent can have left over after covering the floor? Please show your work if possible (like steps etc) You can solve it as a Geometry or in Algebric way which ever works for you. Thankyou To All That Solves!
24 in by 24 in 6 rows 4 in high 3 columns 8 in wide that's 18 pieces 4 by 8 4 triangles will make one such piece 2 of the squares will make one such pieces that's a total of 20 pieces 4 by 8 so there'll be 2 of those pieces left over
Havn't been in an Math class in 4 years now... I'm saying 4 - 4x4 squares will be the smallest amount possible. 16 2x8 right triangles would be the same as 8 2x8 rectangles that = 128 inches, from the 2ftx2ft Square would leave 448 inches. the 10 4x8 rectangles would be 320 inches, leaving 128 inches to fill 8 of the 12 4x4 squares would equal exactly 128 inches and would leave 4 4x4 squares with all area filled. Sounds good, might be missing somthing though.
