like the steps and what it is?
A fireman who is a horizontal distance away of R 50 meters away from a building, directs a stream of water from a fire hose at an angle of θ 30 degrees above horizontal. The water leaves the hose at a speed of V0 (V initial) 40 m/s. A) At what height H does the water strike the building? Vox Vx Vo*cos 30 40*(√3)/2 20√3 m/sec time t X/Vx 50/(20√3) (2.50√3)/3 sec h Vo*sin 30°*t-g/2*t^2 40*0.5*(2.50√3)/3-4.9*6.25/3 18.66 m B) Is the water rising or falling when it strikes the building? top height Voy^2/2g (40*0.5)^2/19.6 400/19.6 20.4 m 18.66 .then water is falling C) At what time has the speed of the water been reduced to Vi 36 m/s? Vx 20*√3 sec Vy √Vi^2-Vx^2 √36^2-1200 ± 9.80 m/sec ± 9.80 Vox-9.8*t t1 (40*0.5-9.8)/9.8 1.041 sec ( ascending water) t2 (40*0.5+9.8)/9.8 3.041 sec ( descending water)
Coz it puts the fire out! You smother it by rolling. Unless you want to stand still and burn to death.
