Master Hello a machine requires 500 speed matching 6-pole motor frequency converter transferred to about 28HZ
6-pole motor synchronous speed of 1000 r / min, the actual motor speed is lower than the number, the actual speed is required to 500 r / min, then the motor and passive pulley diameter ratio of about 1: 1.6 or so, and then specific With the inverter to speed up to achieve the purpose, please refer to.
The belt rotation is calculated by the speed ratio. The current transferred to the motor by the inverter is approximately equal to the rated current of the motor, ie the motor's power is maximized.
If the machine needs the same speed, constant 500r / min
This can be directly with the motor, remove the inverter, but also save costs, while the motor at 50Hz, the maximum power point of rated power. Output torque is the most stable point. The pulley diameter becomes smaller and the reduction ratio increases, and the torque required by the motor becomes smaller, which is advantageous for the motor. 960/500 = 1.92, that is to say the motor pulley compared to the original tune less 1.92 times
