Motor speed is 1440, I want 15 rpm, how to choose the reducer. The gear ratio is how much, how to calculate, thank you
All driving wheels in the mechanism except all driven wheels. I=z1*z2*z3*z4/z2*z3*z4, Z1 is the number of teeth of the driving wheel, and Z2 is the number of teeth of the driven wheel
Of course, they are discrete and horizontal, because the locations of the oil plugs are different. Now the basic unit of speed is rpm, the output speed you need is 900rpm, ratio of formula i=n1/n2=1440/900=1.6, then you can combine the relevant manufacturers reducer sample selection according to the structure and the ratio you need. Of course, also consider the service factor and motor accessories, etc., according to the needs of the fixed. The output torque you need is T=9550*P/n2, P is the motor power, and N2 is the output speed. Hope to help you.
First of all, to determine the structure of the reducer, there are coaxial type, parallel shaft type and straight axis type; secondly, to determine the installation method of the reducer, there are installation of the foot, flange installation,
