One charged plastic ball is vertically above another in a test tube. The balls are in equilibrium a distance d apart. If the charge on each ball is doubled, the distance between the balls in the test tube would become:a. 4db. 2dc. 8d
Equilibrium is established when the electric force between the balls = weight of upper ball .. this force is constant at any spacing. F = k.q1.q2 / d? .. .. For constant F .. q1.q2 ∝ d? .. .. d ∝ √(q1.q2) When q1 and q2 double .. (q1.q2) increases by a factor of 4 .. and d by a factor √4 = 2 Ans .. ?(b).2d
