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Periodic table related questions?

why does Fe^2+ get oxidized more easily to Fe^3+ than Mn^2+ to Mn^3+?does it have something to do with electron configurations?also, why does aluminum have a lower ionization energy than Mg?

Answer:

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Fe 26 [Ar] 4s2 3d6 Fe2+ [Ar] 3d6 Fe3+ [Ar] 3d5 Mn 25 [Ar] 4s2 3d5 Mn2+ [Ar] 3d5 Mn3+ [Ar] 3d4 from the data above, we can see Fe3+ is more stable than Mn3+orbital D has five empty spaces each to be filled with paired electronsthere are two stable condition for orbital D1the spaces are filled with five pairs of electrons 2the spaces are half-filled, which means each space is filled by one unpaired electron orbital D always obey this ruleif for example, the configuration is 4s2 3d4 it will turn into 4s1 3d5, and so does happen to config 4s2 3d9 turning into 4s1 3d10and in Fe3+ the spaces in orbital D are half-filledFe2+ has tendency to get into more stable Fe3+, when Mn2+ has no such tendencytherefore, Fe2+ is easier to be oxidizedalthough Mg supposed to has lower ionization energy according to its position in periodic table, aluminum has more unstable electron configurationAl 13 1s2-2s2-2p6-3s2-3p1 ionization energy is the amount of energy needed to release an electron from the last orbitaluminum has one unpaired electron in the third orbitalcompare it to Mg 12 which the last orbit is 3s23s2 is more stable, since the electrons are pairedpaired electrons with stable configuration needs more ionization energy.

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