Two current carrying wires are perpendicular to each other.Wire 1 is placed on top of wire 2.Wire 1 current direction is pointing North, wire 2 current direction is pointing east. Is there a force on either of the two wires?Does one wire spin due to the produced force?Please explain to me how to do this questionThanks
very confusing subject. look into on to bing and yahoo. just that can assist!
There is no force between the wires. Draw a daigram and use maxwell's screw rule to find direction of magnetic fields created....since both are perpendicular, no combination of fields are seen. Thereby, n movement seen.
Two Current Carrying Wires
Take your right hand and point its thumb to the North representing conventional current flow (Plus to Minus) in the top wire. Visualize the curl of your right hand's fingers can now be replaced be visualizing a bike tire rotating from nuckles to fingernail. Now do the same with the wire having current going East. Contact the two bike tires together a some infinitesimal spot. If those tires are exactly perpendicular in the X and Y (Z doesn't seem to matter because it is the point where they touch), it would make sense to predict that on top a vector will point West and on the bottom a vector will point South. The net vector should be SW. So, if you marked the initial point of cross over on the wires and mechanically could keep them free to move but still perpendicular, the cross over point would move SW for as long as equal current flowed in the two wires.
