A toy of 2.8N is suspended by two wires from a horizontal beam.One wire is 40 degrees to the vertical of the beam.The other is at 60 degrees to the beam.What is the tension in each wire?
The horizontal tensions in the two wires must be equal. The vertical tensions must add to 2.8N. Let the tension in the wires be t1 and t2. t1 * sin(40) <== horizontal tension in wire 1 t1 * cos(40) <== vertical tension in wire 1 t2 * sin(60) <== vertical tension in wire 2 t2 * cos(60) <== horizontal tension in wire 2 t1^2 = (horizontal tension in wire 1)^2 + (vertical tension in wire 1)^2 t2^2 = (horizontal tension in wire 2)^2 + (vertical tension in wire 2)^2
