In a car lift, compressed air exerts a force on a piston with a radius of 7 cm. This pressure is transmitted to a second piston with a radius of 18cm. How large a force must be exerted on the small piston to lift a 1.42x10^4 Newton car? What pressure produces this force?
(49/324)*1.42*10^4 2150 (3sf) hope that helps, area/area * force
? the pressure of compressed air PF1/S1F2/S2, where F11.42·10^4 N is weight of the car, area of piston under the car S1pi*r1^2, r118cm0.18m, while area of pump piston S2pi*r2, r27cm0.07m; thus force exerted by pump ? F2F1*(S2/S1) F1*(r2/r1)^2 1.42·10^4 *(7/18)^2 2148 N; yes Mr. above is right!
The hydraulic lift is based on PASCAL'S LAW Pascal's law states that if excess of pressure is created in any part of a confined liquid,then the excess of pressure is equally transmitted UNDIMINISHED to all parts of the liquid and to the walls of the container If 'f' is force on smaller piston of radius 'r'7 cm ( say area 'a') 'F' is force on bigger piston of radius 'R'18cm (say area 'A') Given F1.42x10^4 newton f ? Then from Pascal's Law, [ f / a ] [ F / A ] gives f F (a/A) f F (r/R)^2 f 2147.53 newton Pressuref/a Pressure2143.53 / pi*0.07*0.07 Pressure139506.18 pascal
