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Question:

Power flow conversion of water pump

I would like to ask, the pump power and flow, there is no formula can be converted? For example, the flow of 9000 tons / hour, then how many units to accompany, how many kilowatts of water pump?

Answer:

Upstairs in Wurenzidi, pump power is related to the flow and the head, a simple formula: = /367 * power flow lift efficiency
Pump shaft power (kw) = water supply (L / s) x lift (m) /102 * efficiency = flow * lift * density * acceleration of gravity.Explanation:102 is the unit collation constant.Pump effective power / pump shaft power = pump efficiency (general 50%--90%, large pump higher)Unit time pump liquid volume flow is, flow by Q, a unit of measure: m3 / h (m3/h), L / S (l/s), L/s=3.6 m3/h=0.06 m3/min=60L/minG=Q G refers to weight - liquid proportionThe energy obtained by pumping a liquid of a unit weight is called a lift. The pump head, including suction stroke, is approximately the difference between the pump outlet and inlet pressure. The lift is expressed in H, and the unit is m.The efficiency of a pump is the ratio of the effective power to the axial power of the pump. ETA =Pe/P pump power usually refers to the input power, the motive power to the pump shaft, it is also called the shaft power, denoted by P. Effective power is the product of pump head and mass flow and gravity acceleration

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