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Question:

Pump power ratio design is small, the problem is big?

Which professional friends ask, I encountered a problem in the design of fire pump head 90 meters, flow rate is 20/S, power is 37KW, but the construction side to buy the pump head and flow are achieved, but the power is only 30KW, this relationship? If you can, let me know by the way, thank you

Answer:

The flow is 20 L/S! Q = 20, L/S = 0.02 m^3/SThe total efficiency of the pump and the motor is estimated to be 60%P=pgHQ/n=1000*9.8*90*0.02/60%=29400W= 29.4, KWLook at the water pump motor power 30KW just enough from the calculation, but there is no room for the use of the attention do not overload!(Note: motor power matching pump nameplate are generally too large, room.)
Lift and flow to meet the requirements of power, in fact little difference, different manufacturers and brands in the same common effect of different power phenomenon, design principle is on the one hand, the hysteresis loss mechanical loss processing technology is one of the reasons of the differences. Power, after all, does not increase, and does not have a major impact on other lines.
No problem, despite the good use of different water pump factory manufacturing process is different, the product of the rich value of different factors, power difference is inevitable, as long as the flow and head to meet your use requirements.The calculation formula tells you: your flow is 72 tons / hour, lift 90 meters, motor power P=2.73HQ/0.75*1.2=28.5KW

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