Put a large beaker of water on a horizontal platform and put a light glass upside down in the water
Rise slowly lifts A certain height, because the process is slow cooling can in time, and the environment temperature balance, and can be regarded as constant temperature, the glass is immersed in the water depth increases, the gas pressure increase, to A.
The inside of the large beaker is raised, the pressure on the surface of the large beaker is larger, and C is right. The pressure of the bracket on the glass is downward, the pressure of the gas is rising, the glass gravity is constant, the pressure of the bracket is greater for the glass, and the D is wrong
Although the inside of the glass is going up, the increase in the pressure of the gas is less than the glass, so B is right.
