AL2 O3+3 CU gt; 2Al+3 CuOIF you have 408 grams of Al2 o3(aluminum oxide)and an unlimited supply of Cu how many grams Al can you produce(round to the nearest gram).show caculations
SALT DOUGH Combine 1 cup of table salt, 1/2 cup of cornstarch, and 3/4 cup of waterHeat the mixture in the top of a double boiler over boiling water, stirring constantlyIn about 2 to 3 minutes the mixture thickens and reaches the consistency of unbaked bread doughRemove from the heat and allow it to cool; then knead for several minutesStore in an airtight plastic bagThis dough can be used to depict formationsYou can put it on any flat surface, such as paper, and it will harden as it dries.
The CofT in your recipe is just a smoothing agent so the flour mixture is less grainy and that's all, it can be omitedAs for the air drying time it depends on the mass of your project, small could dry in a day but if they are large then sorry, it'll take up to a weekYou can speed dry by using the oven set at 200 degrees.
Determine the weight of 1 mole of Al2C3 Al 27 x 2 54 grams O 16 x 3 48 grams Added they total 102 grams per moleFind the percent of a mole each is by dividing amount of element by total: 54 divided by 102 53% Aluminum 48 divided by 102 47% Oxygen (added they total 100%) Given 408 grams, 53% .53 x 408 216 grams Aluminum 48% .48 x 408 192 grams Oxygen Aluminm in reactant Al2 27 x 2 54 grams Aluminum in product 2Al 27 x 2 54 grams 54:54 ratio of 1:1 216 grams 216 grams Answer is 216 grams Aluminum
