The actual power consumed by a three-phase AC motor is equal to line voltage * line current. How do you explain that?
The calculation formula of three-phase symmetrical load; power line I U 3 P= V COS line with =3I2R.Line voltage refers to the parallel voltage between the two phase lines (A-B, A-C, B-C), and the phase voltage refers to the parallel voltage of the relative zero (A-0, B-0, C-0).In the three-phase four wire distribution system neutral directly grounding; line voltage is equal to the phase voltage of 3 V, the phase voltage is equal to 3 V / line voltage, line current is equal to phase.
For the three-phase motor whether delta or star connection, is the P= root 3*380v*I line *COS, line voltage 380V means, the other is right, you do not know where it comes from the formula. If you do not take the appropriate 3, that is the single phase load.
I guess the questioner didn't know the difference between the line voltage, the line current and the phase voltage, the phase current.Line voltage and line current are considered when standing on the power supply side or standing outside the power equipment, while the phase voltage and phase current are considered in the interior of the power equipment. Of a global quantity represented by a physical quantity such as power, the use of line voltage and line current will, of course, be more convenient and direct.
Line voltage, the line current represents the input of the motor, of course, is related to the actual power consumed by the three-phase motor. But also should be multiplied by the square root of 3, but also multiplied by the power factor, is the actual power consumption.
