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Question:

The arm of a crane at a construction site is 12.1 m long, and it makes an angle of 30° with the horizontal.?

The arm of a crane at a construction site is 12.1 m long, and it makes an angle of 30° with the horizontal. Assume that the maximum load the crane can handle is limited by the amount of torque the load produces at the base of the arm. (a) What is the magnitude of the maximum torque the crane can withstand if the maximum load the crane can handle is 500 N?(b) What is the maximum load for this crane at an angle of 35° with the horizontal?

Answer:

(a) What is the magnitude of the maximum torque the crane can withstand if the maximum load the crane can handle is 500 N? τ = FL τ = 500(12.1cos30) τ = 5239.45 τ = 5240 Ν?m (b) What is the maximum load for this crane at an angle of 35° with the horizontal? τ = FL F = τ / L F = 5239.45 / 12.1cos35 F = 528.6109... F = 529 N I hope this helped. Please remember to vote a Best Answer from among your results. It's good karma as it keeps things in balanced exchange.

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